95 240 A m { }_{95}^{240} \mathrm{Am} 95 240 Am decays through what emission?A) Gamma raysB) Beta particlesC) Alpha particlesD) None of the above

Question

95 240 A m { }_{95}^{240} \mathrm{Am} 95 240 ​ Am   decays through what emission?A) Gamma raysB) Beta particlesC) Alpha particlesD) None of the above

Zybrea Knight · Accepted Answer

Final Answer : C, Explanation :   Americium-240 (  95 240 A m { }_{95}^{240} \mathrm{Am} 95 240 ​ Am  ) primarily decays by emitting alpha particles, which are helium-4 nuclei consisting of two protons and two neutrons.

$}_{95}^{240} \mathrm{Am}$ decays through what emission?

A) Gamma rays
B) Beta particles
C) Alpha particles
D) None of the above

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Related questions

95240Am{ }_{95}^{240} \mathrm{Am}95240​Am decays through what emission?A) Gamma raysB) Beta particlesC) Alpha particlesD) None of the above

Definitions

Learning Objectives

Learning Objectives

Related questions

$}_{95}^{240} \mathrm{Am}$ decays through what emission?

A) Gamma rays
B) Beta particles
C) Alpha particles
D) None of the above